y=4y^2+8y-8

Solution for y=4y^2+8y-8 equation:

y=4y^2+8y-8

We move all terms to the left:

y-(4y^2+8y-8)=0

We get rid of parentheses

-4y^2+y-8y+8=0

We add all the numbers together, and all the variables

-4y^2-7y+8=0

a = -4; b = -7; c = +8;
Δ = b2-4ac
Δ = -72-4·(-4)·8
Δ = 177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{177}}{2*-4}=\frac{7-\sqrt{177}}{-8}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{177}}{2*-4}=\frac{7+\sqrt{177}}{-8}
$